1 solutions

  • 1
    @ 2025-12-28 9:11:49
    #include<bits/stdc++.h>
    using namespace std;
    typedef long long LL;
    const int N=2e5+10;
    int a[N],b[N],c[N];
    int main()
    {
    	int n;
    	cin>>n;
    	n*=2;
    	for(int i=1;i<=n;i++)
    	{
    		cin>>a[i];
    	}
    	LL sum=0;
    	for(int i=1;i<=n;i++)
    	{
    		cin>>b[i];
    		c[i]=a[i]-b[i];
    		sum+=b[i];
    	}
    	sort(c+1,c+1+n);//按照从小到大排序
    	for(int i=n/2+1;i<=n;i++) //选择后半段(和越大越好) 
    	{
    		sum+=c[i];	
    	} 
    	cout<<sum;
    } 
    
    • 1

    Information

    ID
    2567
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    5
    Tags
    # Submissions
    7
    Accepted
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    Uploaded By