1 solutions
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0
#include<bits/stdc++.h> using namespace std; const int N=110; int g[N][N]; int dx[]={-1,-1,-1,0,0,1,1,1}; int dy[]={-1,0,1,-1,1,-1,0,1}; int main() { int n,m; cin>>n>>m; for(int i=1;i<=n;i++) { for(int j=1;j<=m;j++) { cin>>g[i][j]; } } int cnt=0; for(int i=1;i<=n;i++) { for(int j=1;j<=m;j++) { bool st=1; for(int k=0;k<8;k++) { int a=i+dx[k],b=j+dy[k]; if(a<1||a>n||b<1||b>m) continue; if(g[i][j]>g[a][b]) { st=0; } } if(st) cnt++; } } cout<<cnt; return 0; }
- 1
Information
- ID
- 3063
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 10
- Tags
- # Submissions
- 7
- Accepted
- 2
- Uploaded By