1 solutions
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1
#include<bits/stdc++.h> using namespace std; int main() { double x,y,n,p; cin>>x>>y>>n>>p; double m=p; //算出第一种优惠多少元 if(p>=x) { m=p-y; } n=n*0.1; double v=p*n; //算出第二种优惠多少元 // 对比那个便宜一些 if(m>v) { cout<<fixed<<setprecision(2)<<v;// } else { cout<<fixed<<setprecision(2)<<m; } return 0; }
- 1
Information
- ID
- 2884
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 7
- Tags
- # Submissions
- 82
- Accepted
- 16
- Uploaded By