3 solutions

  • 1
    @ 2026-3-22 11:23:05
    #include<bits/stdc++.h>
    using namespace std;
    int a[11111110],b[1111110],c[11111110];
    int main()
    {
        string s1,s2;cin>>s1>>s2;
        reverse(s1.begin(),s1.end());
        reverse(s2.begin(),s2.end());
        int lena=s1.size(),lenb=s2.size(),lenc=max(lena,lenb)+1;
        for(int i=0;i<lena;i++)
        {
            a[i]=s1[i]-'0';
        }
        for(int i=0;i<lenb;i++)
        {
            b[i]=s2[i]-'0';
        }
        for(int i=0,t=0;i<=lenc;i++)
        {
            if(a[i]<b[i])
            {
                a[i]+=10;
                a[i+1]-=1;
            }
            c[i]=a[i]-b[i];
            c[i]=c[i]%10;
        }
        while(lenc&&c[lenc]==0) lenc--;
        for(int i=lenc;i>=0;i--)
        {
            cout<<c[i];
        }
        return 0;
    }
    
    • -1
      @ 2025-3-29 16:04:39
      #include<bits/stdc++.h>
      using namespace std;
      const int N=260;
      int a[N],b[N],c[N];
      string s1,s2;
      int main()
      {
      	cin>>s1>>s2;
      	int lena=s1.size();
      	int lenb=s2.size();
      	int lenc=max(lena,lenb)+1;
      	for(int i=0,j=s1.size()-1;j>=0;i++,j--)
      	{
      		a[i]=s1[j]-'0';
      	}
      	for(int i=0,j=s2.size()-1;j>=0;i++,j--)
      	{
      		b[i]=s2[j]-'0';
      	}
      	int t=0;
      	for(int i=0;i<=lenc;i++)
      	{
      		t=t+a[i]+b[i];
      		c[i]=t%10;
      		t/=10;
      	}
      	while(lenc>0&&c[lenc]==0) lenc--;
      	for(int i=lenc;i>=0;i--)
      	{
      		cout<<c[i];
      	}
          return 0;
      }
      
      • -4
        @ 2025-3-29 16:04:17
        #include<bits/stdc++.h>
        using namespace std;
        const int N=210;
        int a[N],b[N],c[N];
        string s1,s2;
        int main()
        {
        	cin>>s1>>s2;
        	int lena,lenb,lenc;
        	lena=s1.size();
        	lenb=s2.size();
        	lenc=lena;
        	for(int i=0,j=lena-1;j>=0;i++,j--)
        	{
        		a[i]=s1[j]-'0';
        	}
        	for(int i=0,j=lenb-1;j>=0;i++,j--)
        	{
        		b[i]=s2[j]-'0';
        	}
        	int t=0;
        	for(int i=0;i<lenc;i++)
        	{
        		c[i]=a[i]-b[i]+t;
        		if(c[i]<0)
        		{
        			c[i]+=10;
        			t=-1;
        		}
        		else
        		{
        			t=0;
        		}
        	}
        	while(lenc>0&&c[lenc]==0) lenc--;
        	for(int i=lenc;i>=0;i--)
        	{
        		cout<<c[i];
        	}
        	return 0;
        }
        
        • 1

        Information

        ID
        143
        Time
        1000ms
        Memory
        256MiB
        Difficulty
        3
        Tags
        (None)
        # Submissions
        99
        Accepted
        35
        Uploaded By