3 solutions

  • 3
    @ 2025-9-22 17:47:42
    #include<bits/stdc++.h>
    using namespace std;
    const int N=210;
    int a[N],b[N],c[N];
    int main()
    {
    	string s1,s2;
    	cin>>s1>>s2;
    	reverse(s1.begin(),s1.end());
    	reverse(s2.begin(),s2.end());
    	for(int i=0;i<s1.size();i++)
    	{
    		a[i]=s1[i]-'0';
    	}
    	for(int i=0;i<s2.size();i++)
    	{
    		b[i]=s2[i]-'0';
    	}
    	int lenc=max(s1.size(),s2.size())+1;
    	for(int i=0,t=0;i<lenc;i++) //t表示进位
    	{
    		c[i]=a[i]+b[i]+t;
    		t=c[i]/10;
    		c[i]=c[i]%10;
    	}
    	while(lenc&&c[lenc]==0) lenc--;
    	for(int i=lenc;i>=0;i--)
    	{
    		cout<<c[i];
    	}
    	return 0;
    }
    
    • 2
      @ 2025-3-9 13:40:13
      #include<bits/stdc++.h>
      using namespace std;
      const int N=260;
      int a[N],b[N],c[N];
      string s1,s2;
      int main()
      {
      	cin>>s1>>s2;
      	int lena=s1.size();
      	int lenb=s2.size();
      	int lenc=max(lena,lenb)+1;
      	for(int i=0,j=s1.size()-1;j>=0;i++,j--)
      	{
      		a[i]=s1[j]-'0';
      	}
      	for(int i=0,j=s2.size()-1;j>=0;i++,j--)
      	{
      		b[i]=s2[j]-'0';
      	}
      	int t=0;
      	for(int i=0;i<=lenc;i++)
      	{
      		t=t+a[i]+b[i];
      		c[i]=t%10;
      		t/=10;
      	}
      	while(lenc>0&&c[lenc]==0) lenc--;
      	for(int i=lenc;i>=0;i--)
      	{
      		cout<<c[i];
      	}
          return 0;
      }
      
      • 1
        @ 2026-3-20 19:53:20
        #include<bits/stdc++.h>
        using namespace std;
        const int N=210;
        int a[N],b[N],c[N]; 
        int main()
        {
        	string s1,s2;
        	cin>>s1>>s2;
        	int lena=s1.size();
        	int lenb=s2.size();
        	int lenc=max(lena,lenb)+1;
        	for(int i=0,j=lena-1;j>=0;i++,j--)
        	{
        		a[i]=s1[j]-'0';	
        	}
        	for(int i=0,j=lenb-1;j>=0;i++,j--)
        	{
        		b[i]=s2[j]-'0';
        	}
        	for(int i=0,t=0;i<=lenc;i++)
        	{
        		c[i]=a[i]+b[i]+t;
        		t=c[i]/10;
        		c[i]=c[i]%10;
        	}
        	while(lenc&&c[lenc]==0) lenc--;
        	for(int i=lenc;i>=0;i--)
        	{
        		cout<<c[i];
        	}
        	return 0;
        }
        
        
        • 1

        Information

        ID
        956
        Time
        1000ms
        Memory
        256MiB
        Difficulty
        3
        Tags
        (None)
        # Submissions
        133
        Accepted
        36
        Uploaded By