2 solutions

  • -1
    @ 2025-12-13 15:56:58
    
    
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int x,y,n;
    	cin>>n>>x>>y;
        int t=(y+x-1)/x;
    	int r=n-t;
    	if(r<=0)
    	{
    		r=0;
    	}
    	cout<<r;
    	return 0;
     }
    
    
    
    • -2
      @ 2025-12-13 15:54:49
      #include<bits/stdc++.h>
      using namespace std;
      int main()
      {
      	int a,b,c;
      	cin>>a>>b>>c;
      	if(a>b) //保证 a<=b 
      	{
      		int t=a;
      		a=b;
      		b=t;
      	} 
      	if(a>c) //保证a<=c 
      	{
      		int t=a;
      		a=c;
      		c=t;
      	}
      	if(b>c) //保证b<=c 
      	{
      		int t=b;
      		b=c;
      		c=t;
      	}
      	if(a+1==b&&b+1==c)
      	{
      		cout<<"TRUE";
      	}
      	else
      	{
      		cout<<"FALSE";
      	}
      	return 0;
      }
      
      
      • 1

      Information

      ID
      856
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      1
      Tags
      (None)
      # Submissions
      539
      Accepted
      109
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