1 solutions
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1
#include<bits/stdc++.h> using namespace std; int a[5010]; int main() { int n,m; cin>>n>>m;//n纸杯个数,m操作次数; for(int i=1;i<=n;i++)//输入每个杯子上的数 { cin>>a[i]; } for(int i=1;i<=m;i++)//操作纸杯交换 { int u,v; cin>>u>>v;//输入两个纸杯 swap(a[u],a[v]); } for(int i=1;i<=n;i++)//循环输出 { cout<<a[i]<<' '; } return 0; }
- 1
Information
- ID
- 2866
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- # Submissions
- 59
- Accepted
- 23
- Uploaded By