7 solutions

  • 6
    @ 2025-4-26 15:11:59
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int a,b;
    	cin>>a>>b;
    	int t=b/a; //计算应该是第几个字母
    	if(b%a==0) t--; //如果是整倍数,商需要减一
    	char c='A'+t;
    	cout<<c; 
    	return 0;
    }
    
    • 5
      @ 2025-12-27 10:28:36

      #include<bits/stdc++.h> using namespace std; int main() { int a,b; cin>>a>>b; int t=b/a;
      if(b%a==0)
      { t--; } char c='A'+t;
      cout<<c; return 0; }

      • 1
        @ 2026-5-16 9:31:53

        #include<bits/stdc++.h> using namespace std; int main() {

        int a,b;
        
        cin>>a>>b;
        
        int t=b/a;
        
        if(b%a==0)
        {
        	t--;
        }
        char c='A'+t;
        
        cout<<c; 
        
        return 0;
        

        }

        • 0
          @ 2026-7-30 11:32:42
          #include<bits/stdc++.h>
          using namespace std;
          int main(){
              int n,x;
              cin>>n>>x;
              int t=0;
              if(x%n==0)
              {
                  t=x/n;
              }
              else
              {
                  t=x/n+1;
              }
              if(t!=0)
              {
                  cout<<char(t+64);
              }
              else
              {
                  cout<<'A';
              }
              return 0;
          }
          
          • 0
            @ 2025-8-11 15:38:23
            #include<bits/stdc++.h>
            using namespace std;
            int main()
            {
            	int n,m;
            	cin>>n>>m;
            	char a=(m/n)+'A'-1;
            	if(m%n!=0) a++;
            	cout<<a;
            	return 0;
            }
            
            • -2
              @ 2026-5-16 9:36:06

              #include<bits/stdc++.h>

              using namespace std;

              int main()

              {

              int a,b;
              
              cin>>a>>b;
              
              int t=b/a;
              
              if(b%a==0)
              
              {
              	t--;
              
              }
              char c='A'+t;
              
              cout<<c; 
              
              return 0;
              

              }

              • -2
                @ 2026-5-16 9:35:19

                #include<bits/stdc++.h>

                using namespace std;

                int main() { int a,b;

                cin>>a>>b;
                
                int t=b/a;
                
                if(b%a==0)
                
                {
                	t--;
                }
                char c='A'+t;
                
                cout<<c; 
                
                return 0;
                

                }

                • 1

                Information

                ID
                2404
                Time
                1000ms
                Memory
                256MiB
                Difficulty
                1
                Tags
                (None)
                # Submissions
                234
                Accepted
                81
                Uploaded By