3 solutions
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0
#include<bits/stdc++.h> using namespace std; #define int long long int n,ans; signed main() { cin>>n; for(int i=1;i<=sqrt(n);i++) { if(n%i==0) { if(i*i==n) { ans++; } else { ans+=2; } } } cout<<ans; return 0; }#include<bits/stdc++.h> using namespace std; #define int long long int n,ans; signed main() { cin>>n; for(int i=1;i<=sqrt(n);i++) { if(n%i==0) { if(i*i==n) { ans++; } else { ans+=2; } } } cout<<ans; return 0; }
Information
- ID
- 33
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 328
- Accepted
- 89
- Uploaded By