2 solutions
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0
#include <bits/stdc++.h> using namespace std; const int N=100010; int a[N]; int main() { int n; cin>>n; int s=0,sum=100010; for(int i=1;i<=n;i++) { cin>>a[i]; s=max(s,a[i]); sum=min(sum,a[i]); } int q=-10000; for(int i=1;i<=n;i++) { for(int j=i+1;j<=n;j++) { if(a[j]-a[i]>q) { q=a[j]-a[i]; } } } cout<<q; return 0; }
Information
- ID
- 3035
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 35
- Accepted
- 8
- Uploaded By