3 solutions

  • 1
    @ 2026-4-6 15:51:28
    #include<bits/stdc++.h>
    using namespace std;
    int arr[110010];
    int main(){
    	cin>>arr[1]>>arr[2];
    	int n,m;
    	cin>>m>>n;
    	int t=0;
    	for(int i=1;i<=n;i++){
    		if(i>=3){
    			arr[i]=arr[i-1]+arr[i-2];
    		}
    		t+=arr[i];
    		if(arr[i]>=m){
    			break;
    		}
    	}
    	cout<<t;
    	return 0;
    }
    
    

    Information

    ID
    2532
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    135
    Accepted
    39
    Uploaded By