3 solutions
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0
#include<bits/stdc++.h> using namespace std; const int N=110; char a[N][N],b[N][N]; int main(){ int n; cin>>n; for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ cin>>a[i][j]; } } for(int i=1;i<=n;i++) { for(int j=1;j<=n;j++){ cin>>b[i][j]; } } for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ if(a[i][j]!=b[i][j]){ cout<<i<<" "<<j<<endl; } } } return 0; }
Information
- ID
- 2454
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 33
- Accepted
- 25
- Uploaded By