5 solutions

  • 1
    @ 2026-7-22 15:06:24
    #include<bits/stdc++.h>
    using namespace std;
    const int N=15;
    int g[N][N];
    int main()
    {
    	int n,d;
    	cin>>n>>d;
    	for(int i=1;i<=n;i++)
    	{
    		for(int j=1;j<=d;j++)
    		{
    			cin>>g[i][j];
    		}
    	}
    	int res=0;
    	for(int i=1;i<=n;i++) 
    	{
    		for(int j=i+1;j<=n;j++) 
    		{
    			int sum=0; 
    			for(int k=1;k<=d;k++)  
    			{
    				sum+=(g[i][k]-g[j][k])*(g[i][k]-g[j][k]);	
    			}
    			int k=sqrt(sum);
    			if(k*k==sum)
    			{
    				res++;
    			}
    		}
    	}
    	cout<<res;
    	return 0;
    }
    

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    Information

    ID
    2136
    Time
    2000ms
    Memory
    1024MiB
    Difficulty
    3
    Tags
    (None)
    # Submissions
    60
    Accepted
    24
    Uploaded By